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I wish to create a bitcoin locking script that takes 3 numbers, every of them are lower than 8 and if sum of three numbers are 15 then script will return true. How am i able to try this?
The one who will redeem the transaction wants to supply solely these 3 numbers.
Thanks
requested 2 days in the past
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That is the smallest script I might give you, at 13 opcodes:
OP_3DUP
OP_ADD
OP_ADD
OP_15 OP_NUMEQUALVERIFY
OP_8 OP_LESSTHAN OP_VERIFY
OP_8 OP_LESSTHAN OP_VERIFY
OP_8 OP_LESSTHAN
It saves some bytes by utilizing OP_3DUP to duplicate all three enter numbers, and one byte by checking the addition first utilizing OP_NUMEQUALVERIFY as an alternative of OP_NUMEQUAL, which saves one OP_VERIFY opcode.
answered 2 days in the past
2
OP_DUP OP_8 OP_LESSTHAN OP_VERIFY
OP_SWAP OP_DUP OP_8 OP_LESSTHAN OP_VERIFY
OP_ROT OP_DUP OP_8 OP_LESSTHAN OP_VERIFY
OP_ADD OP_ADD OP_15 OP_NUMEQUAL
Tracing the execution (for a profitable enter):
- Preliminary: a b c
OP_DUP: a b c cOP_8: a b c c 8OP_LESSTHAN: a b c 1OP_VERIFY: a b cOP_SWAP: a c bOP_DUP: a c b bOP_8: a c b b 8OP_LESSTHAN: a c b 1OP_VERIFY: a c bOP_ROT: c b aOP_DUP: c b a aOP_8: c b a a 8OP_LESSTHAN: c b a 1OP_VERIFY: c b aOP_ADD: c (a+b)OP_ADD: (a+b+c)OP_15: (a+b+c) 15OP_NUMEQUAL: 1
answered 2 days in the past
3